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Question:
For $K_4[Fe(CN)_6]$, coordination number and oxidation state are respectively
For $K_4[Fe(CN)_6]$, coordination number and oxidation state are respectively
Updated On: Jul 28, 2022
- $6$, $6$
- $2$, $2$
- $6$, $2$
- $2$, $6$
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The Correct Option is C
Solution and Explanation
In $K_4[Fe(CN )_6]$, the central metal $Fe$ is surrounded by $6\, CN ^-$ ligands.
Hence, coordination no. of $Fe$ is $6$.
Oxidation state of $Fe = 4 + x + (-6) = 0$
$\Rightarrow x - 2 = 0$
$\Rightarrow x = + 2$
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Concepts Used:
Coordination Compounds
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.
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