Question:

During the detection of acidic radical present in a salt, a student gets a pale yellow precipitate soluble with difficulty in $\text{NH}_4\text{OH}$ solution when sodium carbonate extract was first acidified with dil. $\text{HNO}_3$ and then $\text{AgNO}_3$ solution was added. This indicates the presence of:

Updated On: Nov 26, 2024
  • $\text{Br}^-$
  • $\text{CO}_3^{2-}$
  • $\text{I}^-$
  • $\text{Cl}^-$
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The Correct Option is A

Solution and Explanation

The reactions with \( \text{Ag}^+ \) ions produce different colored precipitates depending on the halide present:

\[ \text{Ag}^+ + \text{I}^- \rightarrow \text{AgI} \quad (\text{Yellow ppt.}) \]

\[ \text{Ag}^+ + \text{Cl}^- \rightarrow \text{AgCl} \quad (\text{White ppt.}) \]

\[ \text{Ag}^+ + \text{Br}^- \rightarrow \text{AgBr} \quad (\text{Pale yellow ppt.}) \]

Since a pale yellow precipitate was obtained, it indicates the presence of \( \text{Br}^- \) ions.

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