Question:
Consider the reaction \(CH_3Cl + NaI \to CH_3I + NaCl\). The name of the reaction and the solvent used to remove \(NaCl\) from the reaction mixture are respectively
Consider the reaction \(CH_3Cl + NaI \to CH_3I + NaCl\). The name of the reaction and the solvent used to remove \(NaCl\) from the reaction mixture are respectively
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Remember: "Finkelstein for Iodine, Swarts for Fluorine." Acetone is used in Finkelstein specifically because of the solubility difference between \(NaI\) and \(NaCl\).
Updated On: Jun 24, 2026
- Wurtz reaction, \(H_2O\)
- Swarts reaction, \(H_2O\)
- Finkelstein reaction, dry acetone
- Williamson reaction, \(H_2O\)
- Fittig reaction, dry acetone
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
The reaction involves the exchange of a halogen atom (chlorine) with another (iodine) in an alkyl halide. This specific halogen exchange is a standard name reaction in organic chemistry.
Step 2: Detailed Explanation:
1. Reaction Name: The reaction of an alkyl chloride or bromide with Sodium Iodide (\(NaI\)) to form an alkyl iodide is known as the Finkelstein reaction.
2. Role of Solvent: Dry acetone is used as the solvent. While \(NaI\) is soluble in acetone, the resulting \(NaCl\) or \(NaBr\) is nearly insoluble in it.
3. According to Le Chatelier’s principle, the precipitation of \(NaCl\) (as a solid) from the solution drives the reaction forward, ensuring high yields of the alkyl iodide.
Step 3: Final Answer:
The reaction is the Finkelstein reaction and the solvent is dry acetone.
The reaction involves the exchange of a halogen atom (chlorine) with another (iodine) in an alkyl halide. This specific halogen exchange is a standard name reaction in organic chemistry.
Step 2: Detailed Explanation:
1. Reaction Name: The reaction of an alkyl chloride or bromide with Sodium Iodide (\(NaI\)) to form an alkyl iodide is known as the Finkelstein reaction.
2. Role of Solvent: Dry acetone is used as the solvent. While \(NaI\) is soluble in acetone, the resulting \(NaCl\) or \(NaBr\) is nearly insoluble in it.
3. According to Le Chatelier’s principle, the precipitation of \(NaCl\) (as a solid) from the solution drives the reaction forward, ensuring high yields of the alkyl iodide.
Step 3: Final Answer:
The reaction is the Finkelstein reaction and the solvent is dry acetone.
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