Consider an optical system consisting of a concave mirror $ M_1 $ and convex mirror $ M_2 $ of radii of curvature $ 60 \,cm $ and $ 20\, cm $ , respectively. Two mirrors are separated by a distance of $ 40\, cm $ . An object $ O $ is placed at a distance $ 80\, cm $ from $ P $ . The final image is formed at a distance
Concave mirror $M_1$ with radius $r_1 = 60\, cm$ Convex mirror $M_2$ with radius $I_2 = 20 \,cm$ Focus, $f_1 = \frac{60}{2} = 30\,cm$ Focus, $f_2 = \frac{20}{2} = 10\,cm$ $OP = 80 = u$ From mirror formula, $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$ From concave minor, the image formed by minor $M_1$ will be $f_1 = -30\,cm$ $ u = - 80\,cm$ $ v = ?$ $ \frac{1}{-0} = \frac{1}{v} + \frac{1}{-80}$ $\frac{1}{v} = \frac{1}{80} - \frac{1}{30} $ $ = \frac{30-80}{80\times 30}$ $ \frac{1}{v} = - \frac{50}{80\times 30}$ $ v = - 48 \,cm$ The image will be out of reflecting surface of mirror $M_2$. So, this will be the final image and it will form on the left of $M_1$.
Was this answer helpful?
0
2
Top Questions on Ray optics and optical instruments
Optics, deals with the determination of behaviour and the properties of light, along with its interactions with the matter and also with the instruments that are used to detect it.
Ray optics is also known as the geometrical optics and it is a branch of science which describes light propagation.
Reflection is the change in direction of light at an interface in-between two different media so that the wave-front returns into a medium from which it was originated.
Speed of light is the rate at which the light travels in free space.
A phenomenal change in image formed when the light is passed from one medium to another which is called Refraction.
Total Internal Reflection is the reflection of light when the light ray enters into a rarer medium from a denser medium and the angle of incidence is higher than the critical angle of incidence then that light ray will be reflected back to the denser medium.
