Question:
Concentrated nitric acid is labelled as 75%by mass. The volume in mL of the solution which contains 30 g of nitric acid is:
Given: Density of nitric acid solution is 1.25 g/mL.
Concentrated nitric acid is labelled as 75%by mass. The volume in mL of the solution which contains 30 g of nitric acid is:
Given: Density of nitric acid solution is 1.25 g/mL.
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When solving mass and volume problems, use the relationship \( {Density} = \frac{{Mass}}{{Volume}} \) to find the missing values.
Updated On: Nov 4, 2025
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The Correct Option is C
Approach Solution - 1
To find the volume of the nitric acid solution that contains 30 g of nitric acid in a solution that is 75% nitric acid by mass, we can follow these steps:
- Calculate the total mass of the solution required to contain 30 g of nitric acid. Since the solution is 75% nitric acid by mass, the formula to find the total mass (mtotal) is given by:
\( m_{\text{HNO}_3} = \frac{75}{100} \times m_{\text{total}} \)
Given that \( m_{\text{HNO}_3} = 30 \) g, we have:
\( 30 = \frac{75}{100} \times m_{\text{total}} \)
\( m_{\text{total}} = \frac{30 \times 100}{75} \)
\( m_{\text{total}} = 40 \) g - Calculate the volume of the solution using its density. The density (\( \rho \)) of the nitric acid solution is given as 1.25 g/mL. We can use the formula:
\( \text{Volume (mL)} = \frac{\text{Mass (g)}}{\text{Density (g/mL)}} \)
Substituting the values:
\( \text{Volume} = \frac{40}{1.25} \)
\( \text{Volume} = 32 \) mL
Thus, the volume of the solution required is 32 mL.
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Approach Solution -2
Step 1: Given data.
Mass percentage of nitric acid = 75% by mass
Density of nitric acid solution = 1.25 g/mL
Mass of pure HNO₃ required = 30 g
Step 2: Relation between mass of solution and mass percentage.
If the solution is 75% by mass, it means:
\[ 75 \, \text{g of HNO₃ is present in 100 g of solution.} \]
Therefore, to get 30 g of HNO₃, we need:
\[ \text{Mass of solution} = \frac{30 \times 100}{75} = 40 \, \text{g}. \]
Step 3: Find the volume of the solution.
Using the density formula:
\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \Rightarrow \text{Volume} = \frac{\text{Mass}}{\text{Density}}. \]
\[ \text{Volume} = \frac{40}{1.25} = 32 \, \text{mL}. \]
Final Answer:
\[ \boxed{32 \, \text{mL}} \]
Mass percentage of nitric acid = 75% by mass
Density of nitric acid solution = 1.25 g/mL
Mass of pure HNO₃ required = 30 g
Step 2: Relation between mass of solution and mass percentage.
If the solution is 75% by mass, it means:
\[ 75 \, \text{g of HNO₃ is present in 100 g of solution.} \]
Therefore, to get 30 g of HNO₃, we need:
\[ \text{Mass of solution} = \frac{30 \times 100}{75} = 40 \, \text{g}. \]
Step 3: Find the volume of the solution.
Using the density formula:
\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \Rightarrow \text{Volume} = \frac{\text{Mass}}{\text{Density}}. \]
\[ \text{Volume} = \frac{40}{1.25} = 32 \, \text{mL}. \]
Final Answer:
\[ \boxed{32 \, \text{mL}} \]
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