Catalyst A reduces the activation energy for a reaction by 10 kJ mol–1 at 300 K.
The ratio of rate constants,
\(\frac{Κ′ , Catalysed}{Κ,Uncatalysed}\)
is ex. The value of x is ____.[nearest integer]
[Assume that the pre-exponential factor is same in both the cases Given R = 8.31 J K–1 mol–1]
The correct answer is 4
\(In \frac{Κ′}{Κ} = \frac{E_a - E′_a}{RT} \)
\(= \frac{10 × 10³}{8.314 × 300}\)
In \(\frac{Κ′}{Κ}\) \(= \frac{100}{8.314 × 3}\)
\(\frac{Κ′}{Κ} = e^4\)
Therefore , x = 4
A body of mass 1000 kg is moving horizontally with a velocity of 6 m/s. If 200 kg extra mass is added, the final velocity (in m/s) is:
All reactants need to overcome certain energy, better known as activation energy in order to form products. This activation energy is the difference between the energy of the transition state and the reactant species.
Catalysis of chemical reactions is generally divided into two categories: