Question

Carrying capacity of a bucket elevator having 4 buckets per meter moving at a speed of 1 m/minute, with bucket holding capacity \(0.1\text{ m}^3\), will be

• A. \(15\text{ m}^3\text{/h}\)
• B. \(15\text{ m}^3\text{/minute}\)
• C. \(0.4\text{ m}^3\text{/minute}\)
• D. \(4\text{ m}^3\text{/h}\)

Hint:

Capacity per minute $= 4 \times 1 \times 0.1 = 0.4\text{ m}^3/\text{min}$. Capacity per hour $= 0.4 \times 60 = 24\text{ m}^3/\text{h}$.

Answer 1

The Correct Option is C

Step 1: Understanding the Concept:
The theoretical volumetric capacity of a bucket elevator is the product of bucket linear passing frequency and individual bucket volumetric holding capacity.
Key Formula or Approach:
\[ Q = n \times v \times q \]
where \(n\) is number of buckets per meter, \(v\) is belt speed (m/min), and \(q\) is capacity per bucket (\(\text{m}^3\)).

Step 2: Detailed Explanation:
Given parameters:
- Bucket spacing density: \(n = 4\text{ buckets/meter}\)
- Elevator linear speed: \(v = 1\text{ m/minute}\)
- Volume per bucket: \(q = 0.1\text{ m}^3\)
Number of buckets discharging per minute:
\[ \text{Buckets/min} = n \times v = 4\text{ buckets/m} \times 1\text{ m/min} = 4\text{ buckets/min} \]
Volumetric carrying capacity per minute:
\[ Q = 4\text{ buckets/min} \times 0.1\text{ m}^3\text{/bucket} = 0.4\text{ m}^3\text{/minute} \]

Step 3: Final Answer:
Therefore, the carrying capacity is \(0.4\text{ m}^3\text{/minute}\), matching option (C).