Step 1: Understand the reaction with \(AgCN\).
Alkyl halides react with
\[
AgCN
\]
to form alkyl isocyanides.
So, I-bromopentane reacts with
\[
AgCN
\]
to give pentyl isocyanide:
\[
C_5H_{11}Br+AgCN \rightarrow C_5H_{11}NC+AgBr
\]
Hence, Assertion (A) is true.
Step 2: Understand the nature of \(AgCN\).
\[
AgCN
\]
is mainly covalent in nature.
Because of this covalent character, the carbon end is not freely available for attack, and the nitrogen end attacks the alkyl halide.
Therefore, alkyl isocyanide is formed.
Step 3: Check the reason.
The reason says that
\[
AgCN
\]
is mainly ionic in nature.
This is incorrect because
\[
AgCN
\]
is mainly covalent in nature.
Hence, Reason (R) is false.
Step 4: Final conclusion.
Thus, Assertion (A) is true but Reason (R) is false.
Therefore, the correct answer is
\[
\boxed{\text{A is true, R is false}}
\]