Question:

Arrange the following steps of Calvin cycle in correct sequence:
A. Reduction,
B. Regeneration of RuBP,
C. Carboxylation,
D. Formation of glucose, E. Formation of triose phosphate. Choose the correct answer from the options given below:

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Calvin cycle begins with carboxylation and ends with regeneration of RuBP.
Updated On: May 19, 2026
  • A, B, C, D, E
  • B, C, A, D, E
  • C, A, E, D, B
  • C, A, D, E, B
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The Correct Option is C

Solution and Explanation

Concept:
Calvin cycle is the pathway of carbon fixation in photosynthesis. It occurs in the stroma of chloroplast.

Step 1: Carboxylation.

The first step is carboxylation, where \(CO_2\) combines with RuBP in the presence of RuBisCO. \[ C=\text{Carboxylation} \]

Step 2: Reduction.

The fixed carbon compound is reduced using ATP and NADPH. \[ A=\text{Reduction} \]

Step 3: Triose phosphate formation.

Reduction produces triose phosphate molecules. \[ E=\text{Formation of triose phosphate} \]

Step 4: Glucose formation.

Some triose phosphate molecules are used to form glucose. \[ D=\text{Formation of glucose} \]

Step 5: Regeneration.

Remaining molecules help regenerate RuBP so that the cycle continues. \[ B=\text{Regeneration of RuBP} \] Therefore, the correct sequence is: \[ C,A,E,D,B \] \[ \therefore \text{Correct Answer is (C)} \]
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