Question:

According to Bohr's theory, the moment of momentum of an electron revolving in the 4th orbit of a hydrogen atom is:

Updated On: Nov 24, 2024
  • \( \frac{8h}{\pi} \)
  • \( \frac{h}{\pi} \)
  • \( \frac{2h}{\pi} \)
  • \( \frac{h}{2\pi} \)
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The Correct Option is C

Solution and Explanation

According to Bohr’s theory, the angular momentum (moment of momentum) \( L \) of an electron in the \( n \)-th orbit is quantized and given by:
\[ L = \frac{n h}{2\pi}, \] where \( h \) is Planck’s constant and \( n \) is the orbit number.

For an electron in the 4th orbit (\( n = 4 \)):
\[ L = \frac{4h}{2\pi} = \frac{2h}{\pi}. \]

Answer: \(\frac{2h}{\pi}\)

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