Question:

A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?

Show Hint

Break the work at the switching point. Compute time for each phase using \(\text{time}=\frac{\text{work}}{\text{rate}}\) and add them.
Updated On: Aug 25, 2026
  • 3 hours 15 min
  • 3 hours 45 min
  • 3 hours 40 min
  • 3 hours 50 min
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Approach Solution - 1

Step 1: Write the single-tap rate. 
One tap fills the tank in 6 hours \(\Rightarrow\) rate \(=\frac{1}{6}\) tank/hour. 

Step 2: Time to fill the first half with one tap. 
\[ t_1=\frac{\text{work}}{\text{rate}}=\frac{\frac12}{\frac16}=3\ \text{hours}. \] 

Step 3: Fill the remaining half with 4 taps (1 existing + 3 new). 
Combined rate \(=4\times\frac{1}{6}=\frac{2}{3}\) tank/hour. 
\[ t_2=\frac{\frac12}{\frac{2}{3}}=\frac{1}{2}\times\frac{3}{2}=\frac{3}{4}\ \text{hour}=45\ \text{minutes}. \] 

Step 4: Total time. 
\[ t_{\text{total}} = t_1+t_2 = 3\ \text{hours}+45\ \text{minutes}=3\ \text{hours }45\ \text{minutes}. \] \[ \boxed{3\ \text{hours }45\ \text{minutes}} \]

Was this answer helpful?
0
0
Show Solution
collegedunia
Verified By Collegedunia

Approach Solution -2

Using direct and inverse proportion instead of rate formulas gives another way to reach the same total time.

  1. 3 hours 15 min: This equals 195 minutes total; subtracting the 180 minutes (3 hours) needed for one tap to fill the first half leaves only 15 minutes for the second half with 4 taps, but 15 minutes is too short for that portion, so this fails.
  2. 3 hours 45 min: This equals 225 minutes; subtracting 180 minutes leaves exactly 45 minutes for the second half, matching the time needed with 4 taps.
  3. 3 hours 40 min: This equals 220 minutes; subtracting 180 leaves 40 minutes, which is close but not exactly the 45 minutes required.
  4. 3 hours 50 min: This equals 230 minutes; subtracting 180 leaves 50 minutes, more than the 45 minutes actually needed.

One tap fills the whole tank in 6 hours, so by direct proportion it fills half the tank in 3 hours. For the second half, since the work is fixed and the number of taps quadruples from 1 to 4, by inverse proportion the time needed is \(\dfrac{3\ \text{hours}}{4}=45\) minutes. Adding the two stages gives \(3\) hours \(45\) minutes.

So the correct answer is 3 hours 45 min.

Was this answer helpful?
0
0