Question:

A stone dropped from the top of a tower reaches ground in 4 s. Height of the tower is $(g = 10 \, m/s^2)$

Updated On: May 12, 2024
  • 20 m
  • 40 m
  • 60 m
  • 80 m
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The Correct Option is D

Solution and Explanation

As, $h = ut + \frac{1}{2} gt^2$
Here, $u = 0 , g = 10 \, m \, s^{-2} , t = 4\,s $
$ \therefore \:\:\:\: h = 0 \times 4 + \frac{1}{2} \times 10 \times 4^2 = 80 \, m $
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