Question:

A spherical drop of capacitance $1 \mu \,F$ is broken into eight drops of equal radius. Then, the capacitance of each small drop is ........

Updated On: Apr 15, 2024
  • $\frac{1}{8}\,\mu F$
  • $8\,\mu F$
  • $\frac{1}{2}\,\mu F$
  • $\frac{1}{4}\,\mu F$
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The Correct Option is C

Solution and Explanation

Potential of a charged sphere is given by the formula
$V =\frac{ kQ }{ R }$
Hence, by $Q = CV$,
$C =\frac{ Q }{ V }=\frac{ R }{ k }$
As per given information, $\frac{ R }{ k }=1 \mu F$
After splitting,
$8\left(\frac{4}{3} \pi r ^{3}\right)=\frac{4}{3} \pi R ^{3}$
$r =\frac{ R }{2}$
Thus, capacitance of each small drop is $V =\frac{ r }{ k }=\frac{1}{2} \frac{ R }{ k }=\frac{1}{2} \mu F$
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