Question

A solution of a compound $X$ in dilute $HCl$ on treatment with a solution of $BaCl_2$ gives a white precipitate of a compound $Y$ which is insoluble in cone. $HNO_3$ and conc. $HCl$. Compound $X$ imparts golden yellow colour to the flame. $\underset{\text{(imparts golden yellow colour)}}{ {X (Solution \,in \,dilute HCl) }}$ $+\, {BaCl2 -> }$$\underset{\text{Whit ppt}}{ {Y}}$ $ {->[\text{Conc}. HNO_3][\text{Conc}.HCl] Insoluble}$ What are compounds $X$ and $Y$ ?

• A. $X$ is $MgCl_2$ and $Y$ is $BaSO_4$
• B. $X$ is $CaCl_2$ and $Y$ is $BaSO_4$
• C. $X$ is $Na_2SO_4$ and $Y$ is $BaSO_4$
• D. $X$ is $MgSO_4$ and $Y$ is $BaSO_4$

Answer 1

The Correct Option is C

$\underset{\text{(X)}}{ {Na2SO4}} {+BaCl2 \to}$ $\underset{\text{(Y)}}{ {BaSO4}} {+2NaCl}$