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A planet exists of mass \(\frac{1}{6}^{th}\) of the earth's mass and radius \(\frac{1}{3}^{rd}\)of the earth's radius. If the escape speed for earth is 11.2km / s then the escape speed for the planet shall be km/s. (nearest integer)
A planet exists of mass \(\frac{1}{6}^{th}\) of the earth's mass and radius \(\frac{1}{3}^{rd}\)of the earth's radius. If the escape speed for earth is 11.2km / s then the escape speed for the planet shall be km/s. (nearest integer)
Updated On: Jan 31, 2024
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Correct Answer: 8
Solution and Explanation
The correct answer is :8
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Concepts Used:
Escape Speed
Escape speed is the minimum speed, which is required by the object to escape from the gravitational influence of a plannet. Escape speed for Earth’s surface is 11,186 m/sec.
The formula for escape speed is given below:
ve = (2GM / r)1/2
where ,
ve = Escape Velocity
G = Universal Gravitational Constant
M = Mass of the body to be escaped from
r = Distance from the centre of the mass
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