A particle moves along a straight line OX. At a time t (in seconds) the distance x (in metres) of the particle from O is given by x = 40 + 12t - t3 How long would the particle travel before coming to rest ?
Particle Coming to Rest: To find when the particle comes to rest, we need to find the time at which the velocity becomes zero.
The velocity function is given as v = 40 + 12t - t3.
Set v = 0 : 0 = 40 + 12t - t3.
Solving this equation for t, we find t = 4 seconds.
To find the distance traveled before coming to rest, use the equation for displacement:
x = \(\int\)(0 to 4) v \(dt\).
Calculating the integral, and we find that the particle travels a distance of 56 meters.
Therefore, the correct option is (C): 56 m
The displacement x of a particle varies with time t as \(x=ae^{- \alpha t} + be ^{\beta t}\), where \(a,b,\) \(\alpha\) and \(\beta\) are positive constants. The velocity of the particle will:
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Linear motion is also known as the Rectilinear Motion which are of two types: