Question:

A particle moves along a straight line OX. At a time t (in seconds) the distance x (in metres) of the particle from O is given by x = 40 + 12t - t3 How long would the particle travel before coming to rest ?

Updated On: Jun 23, 2024
  • 14 m
  • 28 m
  • 56 m
  • 70 m
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The Correct Option is C

Solution and Explanation

Particle Coming to Rest: To find when the particle comes to rest, we need to find the time at which the velocity becomes zero. 
The velocity function is given as v = 40 + 12t - t3
Set v = 0 : 0 = 40 + 12t - t3
Solving this equation for t, we find t = 4 seconds. 
To find the distance traveled before coming to rest, use the equation for displacement: 
x = \(\int\)(0 to 4) v \(dt\)
Calculating the integral, and we find that the particle travels a distance of 56 meters.

Therefore, the correct option is (C): 56 m

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Concepts Used:

Motion in a straight line

The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion. 

Types of Linear Motion:

Linear motion is also known as the Rectilinear Motion which are of two types:

  1. Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
  2. Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.