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Question:
A particle is thrown vertically up with speed 6 m/s. Find maximum height achieved.
A particle is thrown vertically up with speed 6 m/s. Find maximum height achieved.
Updated On: Jun 7, 2022
- 0.9 meter
- 3.6 meter
- 1.8 meter
- 1 meter
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The Correct Option is C
Solution and Explanation
$H = \frac{u^{2}}{2g}=\frac{6^{2}}{2g}=\frac{36}{20}=1.8$
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Concepts Used:
Motion in a Plane
It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions.
Equations of Plane Motion
The equations of motion in a straight line are:
v=u+at
s=ut+½ at2
v2-u2=2as
Where,
- v = final velocity of the particle
- u = initial velocity of the particle
- s = displacement of the particle
- a = acceleration of the particle
- t = the time interval in which the particle is in consideration
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