Question:
A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is
A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is
Updated On: Apr 22, 2026
- \(\frac {\sqrt 5}{\pi}\)
- \(\frac {\sqrt 5}{2\pi}\)
- \(\frac {4\pi}{\sqrt 5}\)
- \(\frac {2\pi}{\sqrt 3}\)
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The Correct Option is C
Solution and Explanation
The correct option is (C): \(\frac {4\pi}{\sqrt 5}\).
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