Question

A parallel beam of light of wavelength $6000\, ?$ gets diffracted by a single slit of width $0.3 \,mm$. The angular position of the first minima of diffracted light is

• A. $2\times 10^{-3}$ rad
• B. $2.8\times 10^{-3}$ rad
• C. $1.8\times 10^{-3}$ rad
• D. $6\times 10^{-3}$ rad

Answer 1

The Correct Option is A

Given, $\lambda=6000\, ?=6000 \times 10^{-10} m$ and $n=0.3 mm =0.3 \times 10^{-3} m$ $0.3 \times 10^{-3} \times \sin \theta=6000 \times 10^{-10}$ $\sin \theta=2 \times 10^{-3}$ or $\theta=2 \times 10^{-3}\, rad$