Question:

A body of mass $m$ rests on horizontal surface, the coefficient of friction between the body and the surface is $\mu$. if the mass is pulled by a force $P$ as shown in the figure, the limiting friction between body and surface will be:

Updated On: Apr 18, 2024
  • $ \mu mg $
  • $ \mu \left[ mg+\left( \frac{P}{2} \right) \right] $
  • $ \mu \left[ mg-\left( \frac{P}{2} \right) \right] $
  • $ \mu \left[ mg-\left( \frac{\sqrt{3}P}{2} \right) \right] $
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The Correct Option is C

Solution and Explanation

Sketch the free body diagrams. Resoles the force $ P $ is horizontal and vertical components.
The free body diagram of the various forces acting on body is shown. $ R $ is the reaction of the surface on mass, $ f_{s} $ is frictional force.

Taking the horizontal and vertical components, we have
$ R=mg-P\,\sin \,30^{\circ }=mg-\frac{P}{2} $
Limiting frictional force is
$ F=\mu R=\mu \left[ mg-\frac{P}{2} \right] $
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration