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Question:
A body is thrown with a velocity of 9.8 m/s making an angle of $ 30{}^\circ $ with the horizontal. It will hit the ground after a time:
A body is thrown with a velocity of 9.8 m/s making an angle of $ 30{}^\circ $ with the horizontal. It will hit the ground after a time:
Updated On: Jun 7, 2022
- 1.5 s
- 1 s
- 3s
- 2s
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The Correct Option is B
Solution and Explanation
The time of flight $ =\frac{2u\sin \theta }{g} $ $ =\frac{2\times 9.8\times \sin 30{}^\circ }{9.8}=1\,s $
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Concepts Used:
Motion in a Plane
It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions.
Equations of Plane Motion
The equations of motion in a straight line are:
v=u+at
s=ut+½ at2
v2-u2=2as
Where,
- v = final velocity of the particle
- u = initial velocity of the particle
- s = displacement of the particle
- a = acceleration of the particle
- t = the time interval in which the particle is in consideration
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