Question:
298 K पर जल में दिए गए लवणों की विलेयता का सही क्रम है :
298 K पर जल में दिए गए लवणों की विलेयता का सही क्रम है :
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सिर्फ \(K_{sp}\) देखकर solubility compare न करें; dissociation stoichiometry भी देखें।
Updated On: Jun 22, 2026
- \(Hg_2Cl_2 \gt AgBr \gt Zn(OH)_2\)
- \(Zn(OH)_2 \gt AgBr \gt Hg_2Cl_2\)
- \(Hg_2Cl_2 \gt Zn(OH)_2 \gt AgBr\)
- \(AgBr \gt Zn(OH)_2 \gt Hg_2Cl_2\)
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The Correct Option is B
Solution and Explanation
पद 1: प्रश्न को समझना
हमें \(K_{sp}\) से solubility compare करनी है।
पद 2: मुख्य सूत्र या दृष्टिकोण
For: \[ AB \rightarrow A^+ + B^- \] \[ K_{sp}=s^2 \] For: \[ A(OH)_2 \rightarrow A^{2+}+2OH^- \] \[ K_{sp}=4s^3 \] पद 3: विस्तृत व्याख्या
For AgBr: \[ s=\sqrt{5\times10^{-13}} \] \[ =7.1\times10^{-7} \] For \(Hg_2Cl_2\): \[ s=\sqrt{1.3\times10^{-18}} \] \[ =1.14\times10^{-9} \] For \(Zn(OH)_2\): \[ 4s^3=10^{-15} \] \[ s=\left(\frac{10^{-15}}{4}\right)^{1/3} \] \[ \approx6.3\times10^{-6} \] Thus: \[ Zn(OH)_2 \gt AgBr \gt Hg_2Cl_2 \] पद 4: अंतिम उत्तर
अतः सही विकल्प (B) है।
हमें \(K_{sp}\) से solubility compare करनी है।
पद 2: मुख्य सूत्र या दृष्टिकोण
For: \[ AB \rightarrow A^+ + B^- \] \[ K_{sp}=s^2 \] For: \[ A(OH)_2 \rightarrow A^{2+}+2OH^- \] \[ K_{sp}=4s^3 \] पद 3: विस्तृत व्याख्या
For AgBr: \[ s=\sqrt{5\times10^{-13}} \] \[ =7.1\times10^{-7} \] For \(Hg_2Cl_2\): \[ s=\sqrt{1.3\times10^{-18}} \] \[ =1.14\times10^{-9} \] For \(Zn(OH)_2\): \[ 4s^3=10^{-15} \] \[ s=\left(\frac{10^{-15}}{4}\right)^{1/3} \] \[ \approx6.3\times10^{-6} \] Thus: \[ Zn(OH)_2 \gt AgBr \gt Hg_2Cl_2 \] पद 4: अंतिम उत्तर
अतः सही विकल्प (B) है।
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