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The capacitance of a parallel plate capacitor becomes \(\frac{4}{3}\) times its original value if a dielectric slab of thickness t=\(\frac{d}{2}\) is inserted between the plates (where d is the distance of separation between the plates). What is the dielectric constant of the slab?
  • BCECE - 2017
  • BCECE
  • Physics
  • Calculating the Capacitance