List of top Physics Questions on Energy in simple harmonic motion

The displacement of a particle is given at time t, by: x = Asin(-2ω t) + Bsin² ω t Then,
For the system given below, find time period of oscillation?
A particle of mass m executes SHM with amplitude a and frequency ν. The average kinetic energy during its motion from the position of equilibrium to the end is:
The potential energy of a simple harmonic oscillator of mass $2\, kg$ at its mean position is $5\, J.$ If its total energy is $9\, J$ and amplitude is $1\, cm$. then its time period is
A point particle of mass 0.1kg is executing S.H.M. of amplitude 0.1m. When the particle passes through the mean position, its kinetic energy is 8×10⁻3J. Obtain the equation of motion of this particle if its initial phase of oscillation is \(45^\circ\).
Magnitude of binding energy of satellite is $E$ and kinetic energy is $K$ .The ratio $E/K$ is
A body oscillates with SHM according to the equation (in SI units), $x = 5 cos \left(2\pi t +\frac{\pi}{4}\right) .$ Its instantaneous displacement at $t = 1$ second is
Two particles P and Q describe S.H.M. of same amplitude and same frequency along the same straight line. The maximum distance between the two particles is \(2A\). The initial phase difference between the particles is:
A tunnel is dug through the centre of the earth and a ball is released in it. It executes S.H.M. with time period:
An instantaneous displacement of a simple harmonic oscillator is \( x = A \cos(\omega t + \pi/4) \). Its speed will be maximum at time
The damping force on an oscillator is directly proportional to the velocity. The units of the constant of proportionality are
$ U $ is the $ PE $ of an oscillating particle and $ F $ is the force acting on it at a given instant. Which of the following is true ?
A long string is stretched by $2\, cm$ and the potential energy is $V$. If the spring is stretched by $10\, cm$, its potential energy will be
The displacement of a particle executing $SHM$ is given by $y=5 \sin \left(4 t+\frac{\pi}{3}\right)$ If $T$ is the time period and the mass of the particle is $2\, g$, the kinetic energy of the particle when $t = T / 4$ is given by
Starting from the origin a body oscillates simple harmonically with a period of 2 s. After what time will its kinetic energy be 75% of the total energy ?
The potential energy of a simple harmonic oscillator, when the particle is half way to its end point is (where $ E $ is the total energy)
The amplitude of a particle executing SHM is 4 cm. At the mean position the speed of the particle is 16 cm/sec. The distance of the particle from the mean position at which the speed of the particle becomes $ 3.5\times {{10}^{4}}K $ cm/s, will be :
The maximum and minimum tensions in the string whirling in a circle of radius 2.5 m are in the ratio 5:3 then its velocity is :
Two point charges $ 3\times {{10}^{-6}}C $ and $ 8\times {{10}^{-6}}C $ repel each other by a force of $ 6\times {{10}^{-3}}N $ . If each of them is given an additional charge $ -6\times {{10}^{-6}}C $ , the force between them will be:
The angular velocity and the amplitude of a simple pendulum is $\omega$ and a respectively. At a displacement x from the mean position if its kinetic energy is T and potential energy is V, then the ratio of T to V is