Ψ1, Ψ2, Ψ3 and Ψ4 are four Hückel molecular orbitals of benzene with orbital energies E1, E2, E3, and E4, respectively.
Ψ1 = \(\frac{1}{2}\)(ФB + ФC - ФE - ФF)
Ψ2 = \(6^{-\frac{1}{2}}\)(ФA - ФB + ФC - ФD + ФE - ФF)
Ψ3 = \(6^{-\frac{1}{2}}\)(ФA + ФB + ФC + ФD + ФE - ФF)
Ψ4 = \(12^{-\frac{1}{2}}\)(2ФA + ФB - ФC - 2ФD - ФE + ФF)
The correct order of the orbital energies is
(The six carbon atoms of benzene are denoted by A to F and ФJ, is the 2pz, orbital of Jth carbon of benzene.)