If the inverse trigonometric functions take principal values, then\(cos^{-1} ( \frac{3}{10} cos (tan^{-1} (\frac{4}{3})) + \frac{2}{5} sin (tan^{-1} (\frac{4}{3})))\)is equal to :
Let \(f(x)=2cos^{−1}x+4cot^{−1}x−3x^2−2x+10,X∈[−1,1]\)If [a, b] is the range of the function, f then 4a – b is equal to :