List of top Mathematics Questions on linear inequalities asked in KEAM

The solution set of \(\left|x + \frac{1}{x}\right| > 2\) is

If $(x-1)(x^2 - 5x + 7) < (x-1)$, then $x$ belongs to

If $|2x-3|<5, x\in\mathbb{R}$, then $x$ lies in the interval

If $\frac{21x-6}{4}-9\le0$ and $\frac{x-1}{3}+1\ge0, x\in\mathbb{R}$ then $x$ lies in the interval

Let $x$ be a real number such that $\dfrac{x-3}{x-2} \geq 1$. Then the solution set of the inequality is:

The shaded region \(ABC\) shown in the diagram is given by the inequalities

The solution set of inequality \( |x+2|<3 \) is

If \(\frac{x+1}{x-1}<2\), then \(x\) lies in the interval

If \(x \neq 11\) satisfies the inequality \(\frac{2x - 21}{x - 11} \geq 3\), then \(x\) lies in the interval

The inequality \(\frac{2x-1}{3}\geq\frac{3x-2}{4}-\frac{(2-x)}{5}\) holds for x belonging to

If the solution set of the inequality \(|a+3x|\leq6\ is\ [\frac{-8}{3},\frac{4}{3}]\), then the value of a is

The solution set of the inequality \(-2\leq\frac{3x+2}{2}\lt7\) is

The set of all integer values of x that satisfy the inequality 19 ≤ 3x ≤ 27 is

If \( \frac{|x-3|}{x-3} > 0 \), then:

If \( |x-1| + |x-3| \leq 8 \), then the values of \( x \) lie in the interval:

The area and perimeter of a rectangle are \(A\) and \(P\) respectively. Then \(P\) and \(A\) satisfy the inequality

The shaded region shown in the figure is given by the inequations: [height=5cm]{Screenshot 2026-05-01 102102.png}

The shaded region shown in the figure is given by the inequations: [height=5cm]{Screenshot 2026-05-01 102102.png}

The shaded region shown in the figure is given by the inequations: [height=5cm]{Screenshot 2026-05-01 102102.png}

If $ |2x-3|

If $ 3\le 3t-18\le 18, $ then which one of the following is true?

Number of integral solutions of $ \frac{x+2}{{{x}^{2}}+1}>\frac{1}{2} $ is

The solution set of the in equation $ \frac{x+11}{x-3}>0 $ is

If $ x $ satisfies the in equations $ 2x-7<11 $, $ 3x+4