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Mathematics
List of top Mathematics Questions on Quadratic Equations asked in KEAM
If the roots of the equation \( x^2 + 2bx + c = 0 \) are \( \alpha \) and \( \beta \), then \( b^2 - c = \)
KEAM - 2014
KEAM
Mathematics
Quadratic Equations
The equation whose roots are the squares of the roots of the equation \( 2x^2 + 3x + 1 = 0 \) is:
KEAM - 2014
KEAM
Mathematics
Quadratic Equations
If \( z_1 = 2\sqrt{2}(1 + i) \) and \( z_2 = 1 + i\sqrt{3} \), then \( z_1^2 z_2^3 \) is equal to:
KEAM - 2014
KEAM
Mathematics
Quadratic Equations
If the complex numbers \( z_1, z_2 \) and \( z_3 \) denote the vertices of an isosceles triangle, right angled at \( z_1 \), then \( (z_1 - z_2)^2 + (z_1 - z_3)^2 \) is equal to:
KEAM - 2014
KEAM
Mathematics
Quadratic Equations
If the roots of the equation \( x^2 + 2bx + c = 0 \) are \( \alpha \) and \( \beta \), then \( b^2 - c = \)
KEAM - 2014
KEAM
Mathematics
Quadratic Equations
The equation whose roots are the squares of the roots of the equation \( 2x^2 + 3x + 1 = 0 \) is:
KEAM - 2014
KEAM
Mathematics
Quadratic Equations
If \( z_1 = 2\sqrt{2}(1 + i) \) and \( z_2 = 1 + i\sqrt{3} \), then \( z_1^2 z_2^3 \) is equal to:
KEAM - 2014
KEAM
Mathematics
Quadratic Equations
If the complex numbers \( z_1, z_2 \) and \( z_3 \) denote the vertices of an isosceles triangle, right angled at \( z_1 \), then \( (z_1 - z_2)^2 + (z_1 - z_3)^2 \) is equal to:
KEAM - 2014
KEAM
Mathematics
Quadratic Equations
If the roots of \( x^2 - ax + b = 0 \) are two consecutive odd integers, then \( a^2 - 4b \) is:
KEAM - 2014
KEAM
Mathematics
Quadratic Equations
If \( \alpha \) and \( \beta \) are the roots of the equation \( x^2 + 3x - 4 = 0 \), then \( \frac{1}{\alpha} + \frac{1}{\beta} \) is equal to:
KEAM - 2014
KEAM
Mathematics
Quadratic Equations
Let
$ {{z}_{1}} $
and
$ {{z}_{2}} $
be the roots of the equation
$ {{z}^{2}}+pz+q=0 $
where p, q are real. The points represented by
$ {{z}_{1}},{{z}_{2}} $
and the origin form an equilateral triangle, if
KEAM - 2007
KEAM
Mathematics
Quadratic Equations
Given
$ tan\text{ }A $
and
$ tan\text{ B} $
are the roots of
$ {{x}^{2}}-ax+b=0 $
. The value of
$ {{\sin }^{2}}(A+B) $
is
KEAM - 2007
KEAM
Mathematics
Quadratic Equations
The argument of the complex number
$ \left( \frac{i}{2}-\frac{2}{i} \right) $
is equal to
KEAM
Mathematics
Quadratic Equations
Suppose that two persons
$A$
and
$B$
solve the equation
$ {{x}^{2}}+ax+b=0 $
. While solving
$A$
commits a mistake in the coefficient of
$ x $
was taken as
$15$
in place of
$-9$
and finds the roots as
$ -7 $
and
$ -2 $
. Then, the equation is
KEAM
Mathematics
Quadratic Equations
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