List of top Chemistry Questions on Law Of Chemical Equilibrium And Equilibrium Constant asked in KCET

At 500 K, for a reversible reaction \(A_{2_{(g)}}+B_{2_{(g)}}⇌2AB_{(g)}\) in a closed container, KC = 2 × 10-5. In the presence of catalyst, the equilibrium is attaining 10 times faster. The equilibrium constant KC in the presence of catalyst at the same temperature is

1 mole of HI is heated in a closed container of capacity of 2 L. At equilibrium half a mole of HI is dissociated. The equilibrium constant of the reaction is 

For the reaction A(g) + B(g) ⇌ C(g) + D(g); ΔH = -QKJ
The equilibrium constant cannot be disturbed by
The chemical equilibrium of a reversible reaction is not influenced by :
Solubility product of CaC2O4 at a given temperature in pure water is 4×10-9 (mol L-1)2. Solubility of CaC2O4 at the same temperature is: