The area of the smaller region enclosed by the curves y2 = 8x + 4 andx2+y2+4√3x-4=0is equal to
The area of the region\(\left\{(x,y) : y² ≤ 8x, y ≥ \sqrt2x, x ≥ 1 \right\}\)is
The area bounded by the curve \(y=|x^2−9| \)and the line y = 3 is
The area of the bounded region enclosed by the curve \(y=3−|x−\frac{1}{2}|−|x+1| \)and the x-axis is