List of top Physics Questions on Projectile motion asked in BITSAT

A block of mass 5 kg is placed on a frictionless incline of angle $30^\circ$. What is the acceleration of the block down the incline? (Take $g = 9.8\, m/s^2$)
A particle is projected vertically upward with an initial velocity of $ 20 \, m/s $. Calculate the maximum height reached by the particle.
A projectile is launched with an initial velocity of \( 20 \, \text{m/s} \) at an angle of \( 30^\circ \) with the horizontal. What is the maximum height reached by the projectile? (Take \( g = 10 \, \text{m/s}^2 \))
The statement “velocity and acceleration always act through the same straight line, either in the same or opposite direction” applies for which dimensional motions?
Two projectiles A and B are thrown with speeds in the ratio 1 : √(2) and acquire the same heights. If A is thrown at an angle of 45^∘ with the horizontal, the angle of projection of B will be
A stone projected with a velocity u at an angle θ with the horizontal reaches maximum height H₁. When it is projected with velocity u at an angle ((π)/(2)-θ) with the horizontal, it reaches maximum height H₂. The relation between the horizontal range R of the projectile, heights H₁ and H₂ is:
A particle of mass 2m is projected at an angle of 45^∘ with the horizontal at a velocity of 20√(2)m/s. After 1s, explosion takes place and the particle is broken into two equal pieces. As a result of explosion, one part comes to rest. The maximum height from the ground attained by the other part is
The position of a projectile launched from the origin at t = 0 is given by r = (40hati + 50hatj)m at t = 2s. If the projectile was launched at an angle θ from the horizontal (take g = 10m s⁻2), then θ is
A hunter aims his gun directly at a monkey on a tree. At the instant the bullet leaves the barrel, the monkey drops. Pick the correct statement regarding the situation.
A juggler keeps on moving four balls in the air throwing the balls after intervals. When one ball leaves his hand (speed = 20m/s), the position of other balls (height in m) will be (Take g = 10m/s²):

Two projectiles, A and B, are thrown with speeds in the ratio 1:√(2) and acquire the same heights. If A is thrown at an angle of 45° with the horizontal, the angle of projection of B will be

A stone projected with velocity u at an angle θ with the horizontal reaches maximum height H₁. When it is projected with velocity u at an angle ((π)/(2)-θ), it reaches maximum height H₂. The relation between the horizontal range R of the projectile, heights H₁ and H₂ is:
A particle of mass \(2m\) is projected at an angle of \(45^\circ\) with the horizontal with a velocity \(20\sqrt{2}\,\text{m/s}\). After \(1\,\text{s}\), an explosion takes place and the particle breaks into two equal pieces. As a result of explosion, one part comes to rest. The maximum height from the ground attained by the other part is:
The position of a projectile launched from the origin at \(t=0\) is given by \[ \vec{r} = (40\hat{i}+50\hat{j})\,\text{m} \quad \text{at } t=2\,\text{s}. \] If the projectile was launched at an angle \(\theta\) from the horizontal (take \(g=10\,\text{m s}^{-2}\)), then \(\theta\) is:
A projectile is fired with a velocity \(u\) making an angle \(\theta\) with the horizontal. What is the magnitude of change in velocity when it is at the highest point?
A projectile is fired with a velocity $u$ making an angle $\theta $ with the horizontal. What is the magnitude of change in velocity when it is at the highest point -
A particle of mass \( m \) is projected with a velocity \( v \) making an angle of \( 30^\circ \) with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height \( h \) is –
A body is projected, making an acute angle \( \theta \) with the horizontal. If angle between velocity \( \vec{v} \) and acceleration \( \vec{g} \) is \( \theta \), then
A particle of mass ' $m$ ' is projected with a velocity $v$ making an angle of $30^{\circ}$ with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height ' $h$ ' is
The range of the particle when launched at an angle of 15° with the horizontal is 1.5 km. What is the range of the projectile when launched at an angle of 45° to the horizontal?
A projectile can have the same range \( R \) for two angles of projection. If \( t_1 \) and \( t_2 \) are the times of flight in two cases, then what is the product of two times of flight?
A passenger in an open car travelling at 30 m/s throws a ball out over the bonnet. Relative to the car, the initial velocity of the ball is 20 m/s at 60^ to the horizontal. The angle of projection of the ball with respect to the horizontal road will be:
A passenger in an open car travelling at $30\, m / s$ throws a ball out over the bonnet. Relative to the car the initial velocity of the ball is $20 m / s$ at $60^{\circ}$ to the horizontal. The angle of projection of the ball with respect to the horizontal road will be :
Two projectiles A and B are thrown with the same speed but at angles 40^ and 50^ with the horizontal. Then
A body is projected vertically upwards at time $ t = 0$ and it is seen at a height $H$ at time $t_1$ and $t_2$ second during its flight. The maximum height attained is ($g$ is acceleration due to gravity)