List of top Mathematics Questions on Straight lines asked in BITSAT

The distance from the origin to the image of $(1, 1)$ with respect to the line $x + y + 5 = 0$ is:

Find the slope of the line passing through the points $ (1, 2) $ and $ (3, 6) $:

Equation of two straight lines are $\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}$ and $\frac{x-4}{5}=\frac{y-1}{2}=z$ .Then

Given the system of straight lines a(2x+y-3)+b(3x+2y-5)=0, the line of the system situated farthest from the point (4,-3) has the equation

The equation $x^2 - 2 \sqrt{3} xy + 3y^2 - 3x + 3 \sqrt{3} y - 4 = 0 $ represents

A ray of light coming from the point $(1, 2)$ is reflected at a point $A$ on the $x$-axis and then passes through the point $(5, 3)$. The co-ordinates of the point $A$ is

The line joining $(5,0)$ to $((10 \cos \theta, 10 \sin \theta)$ is divided internally in the ratio $2: 3$ at $P$. If $q$ varies, then the locus of $P$ is

The number of integral values of $\lambda$ for which $x^2 + y^2 + \lambda x + (1 - \lambda )y + 5 = 0 $ is the equation of a circle whose radius cannot exceed $5$, is

If the lines \(p_1x+q_1y=1\), \(p_2x+q_2y=1\) and \(p_3x+q_3y=1\) are concurrent, then the points \((p_1,q_1), (p_2,q_2)\) and \((p_3,q_3)\) are

If $P_1$ and $P_2$ be the length of perpendiculars from the origin upon the straight lines $x \sec \theta + y cosec \theta = a$ and $x \cos \theta - y \sin \theta = a \cos 2 \theta$ respectively, then the value of $4P_1{^2} + P_2{^2}$.

If the lines \( \ell_1 : \ell m + mn + n = 0 \), \( \ell_2 : mn + m + n = 0 \) are concurrent then

If \( 4a^2 + b^2 + 2c^2 + 4ab - 6ac - 3bc = 0 \), the family of lines \( ax + by + c = 0 \) is concurrent at one or the other of the two points-

The quadratic equation whose roots are the \( x \) and \( y \) intercepts of the line passing through \( (1, 1) \) and making a triangle of area \( A \) with the co-ordinate axes is

The nearest point on the line \( 3x + 4y = 12 \) from the origin is:

Equation of the bisector of the acute angle between lines $3x + 4y + 5 = 0$ and $12x -5y - 7 = 0$ is