Show that \(\frac{\text{Farad}}{\text{meter}} = \frac{\text{coulomb}^2}{\text{newton} \times \text{meter}^2}\). Name its physical quantity. If potential difference across ends of capacitor of capacitance 6 \(\mu\)F is 2 volts, find out the potential difference across ends of the battery :
\begin{center}
\begin{circuitikz}
\draw (0,2) to[C, l=4F] (2,2) to[C, l=6F] (4,2);
\draw (4,2) -- (4,0);
\draw (4,0) to[battery1, l=V] (0,0);
\draw (0,0) -- (0,2);
\end{circuitikz}
\end{center}