Question:

Which one of the following is an ideal transducer for doing ultrasonographic examination of reticulum in a cow?

Show Hint

Ultrasound Probe Selection:
3.5 MHz Probe $\rightarrow$ Deep organs in cattle (Reticulum, Rumen, Liver, Abomasum).
5.0--7.5 MHz Probe $\rightarrow$ Transrectal bovine reproduction Small animal abdomen.
10--12 MHz $\rightarrow$ Superficial tendons Ophthalmic.
  • 3.5 MHz linear transducer
  • 5.0 MHz transducer
  • 7.5 MHz transducer
  • 8.5 MHz transducer
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation


Step 1: Understanding the Concept:

Ultrasound physics: acoustic penetration depth is inversely proportional to transducer frequency ($ ext{Depth} \propto 1/f$), requiring low-frequency 3.5 MHz probes for deep bovine abdominal organs.
Key Formula or Approach:
\[ \text{Penetration Depth: } 3.5\text{ MHz (up to 18--22 cm)} \gg 5.0\text{ MHz (10--12 cm)} \gg 7.5\text{ MHz (3--5 cm)} \]

Step 2: Detailed Explanation:

In bovine diagnostic ultrasonography (examination of the reticulum for Traumatic Reticuloperitonitis Hardware Disease):
- The adult bovine reticulum lies deep within the cranial ventral abdomen ($12 - 20\text{ cm}$ below the skin surface in the 6th to 8th intercostal spaces at the left ventral thorax).
- High-frequency transducers (7.5--8.5 MHz) suffer severe acoustic attenuation and cannot penetrate beyond 4--5 cm.
- A low-frequency 3.5 MHz convex or linear transducer provides deep tissue penetration (up to $18 - 25\text{ cm}$), making it the gold standard probe for visualizing the biphasic reticular contractions, mucosal contour, and peri-reticular fibrinous deposits/abscesses.

Step 3: Final Answer:

Therefore, the ideal transducer is a 3.5 MHz linear transducer, corresponding to option (A).
Was this answer helpful?
0
0