The given circuit consists of NOT gates and AND gates. Let's analyze the circuit step by step.
1. The inputs are \( A \) and \( B \).
2. The first NOT gate takes input \( A \), so it inverts \( A \) to give \( \overline{A} \).
3. The second AND gate takes \( \overline{A} \) and \( B \) as inputs, and the output will be \( \overline{A} \cdot B \).
4. The third AND gate takes \( A \) and \( B \) as inputs, and the output will be \( A \cdot B \).
5. The OR gate then combines the two outputs from the AND gates. The final output is:
\[
\overline{A} \cdot B + A \cdot B
\]
Now, let's check the outputs for inputs (1, 1) and (0, 1):
For inputs \( A = 1 \), \( B = 1 \):
- \( \overline{A} = 0 \), so the output from the first AND gate is \( 0 \cdot 1 = 0 \).
- The output from the second AND gate is \( 1 \cdot 1 = 1 \).
- The final output from the OR gate is \( 0 + 1 = 1 \).
For inputs \( A = 0 \), \( B = 1 \):
- \( \overline{A} = 1 \), so the output from the first AND gate is \( 1 \cdot 1 = 1 \).
- The output from the second AND gate is \( 0 \cdot 1 = 0 \).
- The final output from the OR gate is \( 1 + 0 = 1 \).
Thus, the output for inputs \( (1, 1) \) and \( (0, 1) \) is \( 1 \) and \( 1 \), respectively.
Final Answer: Option (B) \( 0, 0 \).