$-1.6 \times 10^{-15}$ C
Step 1: The charge on a single electron is: \[ e = 1.6 \times 10^{-19} { C} \]
Step 2: The charge on the glass rod is given by: \[ Q = n e \] where $n$ is the number of lost electrons. Given that $n = 1000$, we get: \[ Q = 1000 \times 1.6 \times 10^{-19} \] \[ Q = 1.6 \times 10^{-16} { C} \]
Step 3: Since the rod loses electrons, it becomes positively charged.
Step 4: Therefore, the correct answer is (A).
Kepler's second law (law of areas) of planetary motion leads to law of conservation of
Kepler's second law (law of areas) of planetary motion leads to law of conservation of