The correct answer is (B) : The velocity of atomic oxygen doubles
As
\(v_{rms}=\sqrt{\frac{3RT}{M_0}}\)
T is doubled and oxygen molecule is dissociated into atomic oxygen molar mass is halved.
So,
\(v'_{rms}=\sqrt{\frac{3R×2T_0}{M_0/2}}=2v_{rms}\)
So velocity of atomic oxygen is doubled.
A body of mass 1000 kg is moving horizontally with a velocity of 6 m/s. If 200 kg extra mass is added, the final velocity (in m/s) is: