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Water is flowing through a horizontal tube having cross-sectional areas of its two ends beings $A$ and $A$' such that the ratio $A/A$' is $5$. If the pressure difference of water between the two ends is $3 \times 10^5\, N m^{-2}$, the velocity of water with which it enters the tube will be (neglect gravity effects)
Water is flowing through a horizontal tube having cross-sectional areas of its two ends beings $A$ and $A$' such that the ratio $A/A$' is $5$. If the pressure difference of water between the two ends is $3 \times 10^5\, N m^{-2}$, the velocity of water with which it enters the tube will be (neglect gravity effects)
Updated On: May 20, 2024
- $5\, ms^{-1}$
- $10\, ms^{-1}$
- $25\, ms^{-1}$
- $50\sqrt{10} m s^{-1}$
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The Correct Option is A
Solution and Explanation
Answer (a) $5\, ms^{-1}$
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Concepts Used:
Bernauli Theorem
In fluid dynamics, Bernoulli's principle states that an increase in the speed of a fluid occurs simultaneously with a decrease in static pressure or a decrease in the fluid's potential energy. The principle is named after Daniel Bernoulli who published it in his book Hydrodynamica in 1738.
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