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Two wires having same length and material are stretched by same force. Their diameters are in the ratio $1 : 3$. The ratio of strain energy per unit volume for these two wires (smaller to larger diameter) when stretched is
Two wires having same length and material are stretched by same force. Their diameters are in the ratio $1 : 3$. The ratio of strain energy per unit volume for these two wires (smaller to larger diameter) when stretched is
Updated On: Sep 4, 2024
- $3 : 1$
- $9 : 1$
- $27 : 1$
- $81 : 1$
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The Correct Option is D
Solution and Explanation
Answer (d) $81 : 1$
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Concepts Used:
Hooke’s Law
Hooke’s Law states that for small deformities, the stress and strain are proportional to each other. Thus,
Stress ∝ Strain
Stress = k × Strain … where k is the Modulus of Elasticity.
When a limited amount of Force or deformation is involved then concept of Hooke’s Law is only applicable . If we consider the fact, then we can deviate from Hooke's Law. This is because of their extreme Elastic limits.
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