The correct option is(B): 16 : 9.
\(=\frac{U_A}{U_B}=\frac{mA}{m_B}×\frac{r_B}{r_A}\)
\(=\frac{4}{3}×\frac{4}{3}\)
\(\frac{16}{9}\)
List- I (Layer of atmosphere) | List- II (Approximate height over earth's surface) | ||
A. | F1-Layer | I. | 10 km |
B. | D-Layer | II. | 170-190 km |
C. | Troposphere | III. | 100 km |
D. | E-layer | IV. | 65-75 km |
A body of mass 1000 kg is moving horizontally with a velocity of 6 m/s. If 200 kg extra mass is added, the final velocity (in m/s) is:
The work which a body needs to do, against the force of gravity, in order to bring that body into a particular space is called Gravitational potential energy. The stored is the result of the gravitational attraction of the Earth for the object. The GPE of the massive ball of a demolition machine depends on two variables - the mass of the ball and the height to which it is raised. There is a direct relation between GPE and the mass of an object. More massive objects have greater GPE. Also, there is a direct relation between GPE and the height of an object. The higher that an object is elevated, the greater the GPE. The relationship is expressed in the following manner:
PEgrav = mass x g x height
PEgrav = m x g x h
Where,
m is the mass of the object,
h is the height of the object
g is the gravitational field strength (9.8 N/kg on Earth) - sometimes referred to as the acceleration of gravity.