Question:

Two point dipoles $p \hat{k}$ and $\frac{p}{2} \hat{k}$ are located at $(0,0,0)$ and $(1\, m , 0,2\, m )$ respectively. The resultant electric field due to the two dipoles at the point $(1 \,m , 0,0)$ is

Updated On: Apr 22, 2024
  • $\frac{9 p}{32 \pi \varepsilon_{0}} \hat{k}$
  • $\frac{-7 p}{32 \pi \varepsilon_{0}} \hat{k}$
  • $\frac{7 p }{32 \pi \varepsilon_{0}} \hat{ k }$
  • none of these
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The Correct Option is B

Solution and Explanation

The given point is on axis of $\frac{\hat{p}}{2}$ dipole and at equatorial line of $\hat{p}$ dipole so that field at given point is $\left(\hat{E}_{1}+\hat{E}_{2}\right)$
$\vec{E_{1}}=\frac{2 K(p 2)}{2^{3}}=\frac{K p}{8}(+\hat{k})$
$\vec{E_{2}}=\frac{K p}{1}(-\hat{k}) $
$\vec{E_{1}}+\vec{E_{2}}=-\frac{7}{8} K p(-\hat{k})=-\frac{7 p}{32 \pi \varepsilon_{0}} \hat{k}$
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Concepts Used:

Electric Dipole

An electric dipole is a pair of equal and opposite point charges -q and q, separated by a distance of 2a. The direction from q to -q is said to be the direction in space.

p=q×2a

where,

p denotes the electric dipole moment, pointing from the negative charge to the positive charge.

Force Applied on Electric Dipole