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Question:
Two point dipoles of dipole moment $\overrightarrow{p_{1}}$ and $\overrightarrow{p_{2}}$ are at a distance $x$ from each other and $\overrightarrow{p_{1}} \left|\right| \overrightarrow{p_{2}}.$ The force between the dipoles is :
Two point dipoles of dipole moment $\overrightarrow{p_{1}}$ and $\overrightarrow{p_{2}}$ are at a distance $x$ from each other and $\overrightarrow{p_{1}} \left|\right| \overrightarrow{p_{2}}.$ The force between the dipoles is :
Updated On: Aug 14, 2024
- $\frac{1}{4\pi\varepsilon_{0}} \frac{4p_{1}p_{2}}{x^{4}}$
- $\frac{1}{3\pi\varepsilon_{0}} \frac{8p_{1}p_{2}}{x^{3}}$
- $\frac{1}{4\pi\varepsilon_{0}} \frac{6p_{1}p_{2}}{x^{4}}$
- $\frac{1}{4\pi\varepsilon_{0}} \frac{8p_{1}p_{2}}{x^{4}}$
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The Correct Option is B
Solution and Explanation
Force of interaction
$F = \frac{1}{4\pi\varepsilon_{0}}. \frac{3p_{1}p_{2}}{r^{4}}$
$F = \frac{1}{4\pi\varepsilon_{0}}. \frac{3p_{1}p_{2}}{r^{4}}$
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Concepts Used:
Electric Dipole
An electric dipole is a pair of equal and opposite point charges -q and q, separated by a distance of 2a. The direction from q to -q is said to be the direction in space.
p=q×2a
where,
p denotes the electric dipole moment, pointing from the negative charge to the positive charge.
Force Applied on Electric Dipole
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