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Two cars travel the same distance starting at 10:00 am and 11:00 am, respectively, on the same day. They reach their common destination at the same point of time. If the first car travelled for at least 6 hours, then the highest possible value of the percentage by which the speed of the second car could exceed that of the first car is
Two cars travel the same distance starting at 10:00 am and 11:00 am, respectively, on the same day. They reach their common destination at the same point of time. If the first car travelled for at least 6 hours, then the highest possible value of the percentage by which the speed of the second car could exceed that of the first car is
Updated On: Aug 21, 2024
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The Correct Option is D
Solution and Explanation
The initial car requires 6 hours to reach the destination.
While the second car, starting an hour later, accomplishes the journey in 5 hours, reaching at the same time.
In cases of constant distance, the ratio between speed and time reverse.
The percentage by which the speed of the second car could surpass that of the first car is calculated :
= 1/5 × 100, resulting in 20%.
Hence, the maximum potential percentage by which the speed of the second car could exceed that of the first car is 20%.
While the second car, starting an hour later, accomplishes the journey in 5 hours, reaching at the same time.
In cases of constant distance, the ratio between speed and time reverse.
The percentage by which the speed of the second car could surpass that of the first car is calculated :
= 1/5 × 100, resulting in 20%.
Hence, the maximum potential percentage by which the speed of the second car could exceed that of the first car is 20%.
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