Question:

Two blocks of masses $m$ and $M$ are connected by means of a metal wire of cross-sectional area $A$ passing over a frictionless fixed pulley as shown in the figure. The system is then released. If $M \,= \,2 m$, then the stress produced in the wire is:

Updated On: Jul 11, 2024
  • $\frac{2 m g}{3 A}$
  • $\frac{4 m g}{3 A}$
  • $\frac{m g}{A}$
  • $\frac{3 mg}{4 A}$
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The Correct Option is B

Solution and Explanation

Tension in the wire, $T \approx \left(\frac{2 m M}{m+M}\right) g$ Stress =$\frac{Force/Tension }{Area}=\frac{2 m M}{A \left(m+M\right)} g$ $=\frac{2\left(m \times2m\right)}{A \left(m+2 m\right)} $ (M = 2mgiven) $=\frac{4 m^{2}}{3 m A} g =\frac{4 m g}{3 A}$
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Concepts Used:

Stress and Strain

Stress and Strain are the terms in physics, which are used to explain deformation of solids. 

What is Stress? 

Force applied per unit area is known as stress

  • σ=F/A
  • σ is stress applied
  • F is force applied
  • A is that the area of force applied
  • Stress is measured by unit N/m2

What is Strain?

As a result of stress, change of shape is observed in the body. The change or deformity consequential to the stress acting on the body is called strain. Strain can be defined as the amount or measure of deformity that takes place due to the force applied on the object.

Strain is denoted with (ε). It has no units.

Longitudinal Strain = Δ L/L

Relation Between Stress and Strain

The English scientist Robert Hooke, while studying spring and elasticity, noticed that many materials displayed an identical property when the stress-strain relationship was studied. There exists a linear region where the force required to stretch the material was proportional to the extension of the material; this is called Hooke’s law. Mathematically, the law is presented as:

F = -k.x

Where, F = the force

x = the extension length

k = spring constant in N/m