Question:

Two blocks of masses \(3kg\) and \(1kg\) are placed on a smooth horizontal surface. A horizontal force of \(5N\) acts on the system. Find the contact force between the two blocks.

Show Hint

First calculate the common acceleration of the complete system and then isolate one block to determine the contact force.
  • \(0\,N\)
  • \(5\,N\)
  • \(3.75\,N\)
  • \(1.25\,N\)
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The Correct Option is D

Solution and Explanation



Step 1: Find acceleration of the system.
Total mass \[ M=3+1=4kg \] \[ a=\frac{F}{M} \] \[ a=\frac{5}{4} \] \[ a=1.25m/s^2 \]

Step 2: Determine contact force.
The contact force accelerates the \(1kg\) block. \[ N=ma \] \[ N=1\times1.25 \] \[ N=1.25N \] Final Answer: \[ \boxed{1.25N} \] Hence option \[ \boxed{(D)} \]
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