Question:

Three masses $m,\, 2\, m$ and $3\, m$ are arranged in two triangular configurations as shown in figure $1$ and figure $2$ . Work done by an external agent in changing, the configuration from figure $1$ to figure $2$ is

Updated On: Oct 24, 2024
  • $\frac{6Gm^{2}}{a}\left[2-\frac{6}{\sqrt{2}}\right]$
  • 0
  • $ - \frac{Gm^{2}}{a}\left[ 6 + \frac{6}{\sqrt{2}}\right]$
  • $ - \frac{Gm^{2}}{a}\left[6-\frac{6}{\sqrt{2}}\right]$
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The Correct Option is D

Solution and Explanation

Work done to change configuration from 1 to 2 can be calculated by
$W_{12}=-\left(U_{f}-U_{i}\right)$
$=-\left[-\frac{G m^{2}}{a}\left(2+3+\frac{6}{\sqrt{2}}\right)-\left(-\frac{G m^{2}}{a}(2+3+6)\right)\right]$
$=-\frac{G m^{2}}{a}\left(6-\frac{6}{\sqrt{2}}\right)$
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Concepts Used:

Gravitational Potential Energy

The work which a body needs to do, against the force of gravity, in order to bring that body into a particular space is called Gravitational potential energy. The stored is the result of the gravitational attraction of the Earth for the object. The GPE of the massive ball of a demolition machine depends on two variables - the mass of the ball and the height to which it is raised. There is a direct relation between GPE and the mass of an object. More massive objects have greater GPE. Also, there is a direct relation between GPE and the height of an object. The higher that an object is elevated, the greater the GPE. The relationship is expressed in the following manner:

PEgrav = mass x g x height

PEgrav = m x g x h

Where,

m is the mass of the object,

h is the height of the object

g is the gravitational field strength (9.8 N/kg on Earth) - sometimes referred to as the acceleration of gravity.