Step 1: Setting up the equation.
Let the total length of the pole be \( L \). We are told that:
- Half of the pole is buried in the soil, so \( \frac{L}{2} \) is buried.
- One third of the pole is submerged in water, so \( \frac{L}{3} \) is submerged.
- 2 meters of the pole are out of the water.
Thus, the total length \( L \) satisfies the equation:
\[
\frac{L}{2} + \frac{L}{3} + 2 = L.
\]
Step 2: Solving the equation.
First, find a common denominator:
\[
\frac{3L}{6} + \frac{2L}{6} + 2 = L \implies \frac{5L}{6} + 2 = L.
\]
Subtract \( \frac{5L}{6} \) from both sides:
\[
2 = L - \frac{5L}{6} \implies 2 = \frac{L}{6}.
\]
Multiply both sides by 6:
\[
L = 12.
\]
Step 3: Conclusion.
Thus, the total length of the pole is (B) 12 meters.