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There are three persons A B, and C in a room. If a person D joins the room, the average weight of the persons in the room reduces by x kg . Instead of D , if person E joins the room, the average weight of the persons in the room increases by 2 kg x . If the weight of E is 12 kg more than that of D , then the value of x is
There are three persons A B, and C in a room. If a person D joins the room, the average weight of the persons in the room reduces by x kg . Instead of D , if person E joins the room, the average weight of the persons in the room increases by 2 kg x . If the weight of E is 12 kg more than that of D , then the value of x is
Updated On: Sep 13, 2024
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The Correct Option is C
Solution and Explanation
Let \(A, B, C, D\) and \(E\) weights are \(a, b, c, d\) and \(e\).
According to the ques,
\(\frac {a+b+c}{3}-\frac {a+b+c+d}{4}=x\) ……… (i)
\(\frac {a+b+c+e}{4}-\frac {a+b+c}{3}=2x\) ……… (ii)
Eq (i) + Eq (ii),
\(\frac {a+b+c}{3}-\frac {a+b+c+d}{4}+\frac {a+b+c+e}{4}-\frac {a+b+c}{3}=x+2x\)
\(\frac {e-d}{4}=3x\)
\(e-d = 12x\)
\(12x=12\)
\(x=1\)
So, the correct option is (C): \(1\)
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