Correct answer: 0, 0, 1
Explanation:
Given polynomial: x³ – x²
Factor the expression:
x²(x – 1)
Now, set the polynomial equal to 0:
x²(x – 1) = 0
So the zeroes are:
x = 0 (with multiplicity 2), and x = 1
Hence, the zeroes are: 0, 0, 1
The number of zeroes of a polynomial \( y = p(x) \) as shown below is: