Question:

The velocity of sound in a gas, in which two wavelengths, 4.08 m and 4.16 m produce 40 beats in 12 s, will be:

Updated On: Sep 27, 2024
  • 282.8 ms–1
  • 175.5 ms–1
  • 353.6 ms–1
  • 707.2 ms–1
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The Correct Option is D

Solution and Explanation

The correct answer is (D) : 707.2 ms–1
Beat Frequency = f1 - f2.
\(\frac{v}{4.08} - \frac{v}{4.16} = \frac{40}{12}\)
\(v = \frac{40}{12} × \frac{4.08 × 4.16 }{ 0.08}\)
= 707.2 m/s
 

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Questions Asked in JEE Main exam

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Concepts Used:

Sound

Sound is a vibration that propagates the mechanical wave of displacement and pressure, through a medium can be of any matter. In other words, the sound is the thin line between Music sound and Noise.

Types of Sounds:

Sound can be divided into two types depending on its frequency. The following are:-

Infrasonic Waves:

  • Infrasonic waves have a frequency lower than 20 Hz. Since it is below the human hearing range, it is inaudible to humans.
  • However, several other living organisms use these waves to communicate, whales, sharks, elephants, hippopotamus, etc. these waves are also used in the scientific field, it is used to study upcoming earthquakes, volcanic eruptions, human heart rates, rock formation stages, etc.

Ultrasonic waves:

  • Ultrasonic waves have a frequency higher than 20 kHz. Since it is above the human hearing range, it is inaudible to humans.
  • These waves are used in the scientific field, it is used to study human heart rates, to take sonograms, navigation of directions, imaging things, uniform sample mixing, communication, testing of samples, etc.